Matematika Sekolah Menengah Atas tolong bantuannya kak​, Terimakasih....​

glennielindulv – March 21, 2023

tolong bantuannya kak​, Terimakasih....​

Jawab:

barisan dan deret geometri

(1).

t = 80 cm

r = 1/2

tinggi pantulan = a = 1/2 x 80 =  40

panjang lintasan =  t  + 2 S~

[tex]\rm = t +2( \dfrac{a}{1- r})[/tex]

= 80 + 2(40)/ (1 - 1/2)

= 80 +  80 /1/2

= 80 + 160

=  240cm

________________

*caralain

t= 80

r= 1/2

panjang  pantulan =  (2+ 1)/(2 - 1) x 80

=  3x 80

= 240 cm

(2)

deret konvergen  (x - 1) + (x- 1)² + ( x- 1)³ + . . .

r =  u2/u1

r=  (x- 1)²/(x- 1)

r= x - 1

konvergen  jika  - 1 <  r < 1

-1 < x - 1 < 1  

0 < x < 2

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